Lengkung PES penceraian dengan Qunova HiVQE
Nota
Qiskit Functions ialah ciri eksperimental yang hanya tersedia untuk pengguna Pelan Premium IBM Quantum®, Pelan Flex, dan Pelan On-Prem (melalui API Platform IBM Quantum). Ciri ini berada dalam status pratonton dan tertakluk kepada perubahan.
Anggaran penggunaan (NOTA: Ini adalah anggaran sahaja. Masa jalan anda mungkin berbeza.)
- Li2S: Lima minit masa QPU pada pemproses Heron r2
- FeP-NO: Lima minit masa QPU pada pemproses Heron r2
Latar Belakang​
Mengira tenaga tindak balas kimia dengan tepat adalah penting untuk kemajuan saintifik dalam sains bahan, kejuruteraan kimia, penemuan ubat, dan bidang-bidang lain. Dalam pelbagai sistem kimia, sistem Li-S telah mendapat perhatian besar untuk memahami dan membangunkan komposisi bateri baharu. Tutorial ini memberikan pengalaman praktikal dalam mengira permukaan tenaga potensi (PES) penceraian ikatan Li-S bagi sistem dengan mengeluarkan satu atom litium menggunakan pengiraan HiVQE. Keputusan boleh dibandingkan dengan pengiraan rujukan (CASCI) serta kaedah klasik seperti Hartree-Fock (HF) untuk masalah 20-qubit.
Keperluan​
Pasang kebergantungan berikut untuk menjalankan kod dalam tutorial ini.
!pip install --upgrade pip
!pip install -U qiskit-ibm-catalog "qiskit_ibm_runtime<0.42.0" pyscf numpy matplotlib typing_extensions
Persediaan​
Untuk menjalankan tutorial ini, import fungsi qunova/hivqe-chemistry melalui QiskitFunctionCatalog. Anda memerlukan akaun Pelan Premium IBM Quantum, Pelan Flex, atau Pelan On-Prem (API Platform IBM Quantum) dengan lesen daripada Qunova untuk menjalankan fungsi ini.
from qiskit_ibm_catalog import QiskitFunctionsCatalog
from pyscf import gto, scf, mcscf
import matplotlib.pyplot as plt
import pprint
catalog = QiskitFunctionsCatalog(
channel="ibm_quantum_platform",
instance="INSTANCE_CRN",
token="YOUR_API_KEY", # Use the 44-character API_KEY you created and saved from the IBM Quantum Platform Home dashboard
)
hivqe = catalog.load("qunova/hivqe-chemistry")
Bahagian 1: Li2S (20Q)​
Langkah 1: Petakan input klasik kepada masalah kuantum​
Tentukan geometri dalam format kamus untuk jarak ikatan Li-S yang berbeza bagi mengira lengkung PES. Geometri-geometri ini dioptimumkan menggunakan pengiraan B3LYP/631g.
str_geometries = {
"1.51": "S -1.239044 0.671232 -0.030374; Li -1.506327 0.432403 -1.498949; Li -0.899996 0.973348 1.826768",
"1.91": "S -1.215858 0.692272 0.099232; Li -1.553305 0.390283 -1.758043; Li -0.876205 0.994426 1.956257",
"2.40": "S -1.741432 0.680397 0.346702; Li -0.529307 0.488006 -1.729343; Li -1.284307 0.989409 2.177209",
"3.10": "S -2.347450 0.657089 0.566194; Li -0.199353 0.527517 -1.665148; Li -1.008243 0.973206 1.893522",
"3.80": "S -2.707255 0.674298 0.909161; Li 0.079218 0.552012 -1.671656; Li -0.927010 0.931502 1.557063",
"4.50": "S -2.913363 0.709175 1.276987; Li 0.368656 0.559989 -1.798088; Li -1.010340 0.888647 1.315670",
}
str_geometries
{'1.51': 'S -1.239044 0.671232 -0.030374; Li -1.506327 0.432403 -1.498949; Li -0.899996 0.973348 1.826768',
'1.91': 'S -1.215858 0.692272 0.099232; Li -1.553305 0.390283 -1.758043; Li -0.876205 0.994426 1.956257',
'2.40': 'S -1.741432 0.680397 0.346702; Li -0.529307 0.488006 -1.729343; Li -1.284307 0.989409 2.177209',
'3.10': 'S -2.347450 0.657089 0.566194; Li -0.199353 0.527517 -1.665148; Li -1.008243 0.973206 1.893522',
'3.80': 'S -2.707255 0.674298 0.909161; Li 0.079218 0.552012 -1.671656; Li -0.927010 0.931502 1.557063',
'4.50': 'S -2.913363 0.709175 1.276987; Li 0.368656 0.559989 -1.798088; Li -1.010340 0.888647 1.315670'}
Pengiraan HiVQE akan dilakukan dengan pilihan yang ditentukan di bawah. Menggunakan asas sto3g untuk , terdapat 19 orbital spatial dengan 22 elektron. Untuk menjalankan kes (10o,10e) dengan pengiraan HiVQE, anda boleh menentukan 10 orbital aktif dan enam orbital beku. Pada setiap iterasi, 100 tembakan akan digunakan untuk mengambil sampel konfigurasi elektron yang dijana oleh litar kuantum ExcitationPreserving (epa) dengan jalinan circular dan dua ulangan (reps). Bilangan iterasi maksimum ditetapkan kepada 30 untuk memastikan penamatan iterasi dengan penumpuan tenaga.
molecule_options = {
"basis": "sto3g",
"active_orbitals": list(range(5, 15)),
"frozen_orbitals": list(range(5)),
}
hivqe_options = {
"shots": 100,
"max_iter": 30,
"ansatz": "epa",
"ansatz_entanglement": "circular",
"ansatz_reps": 2,
}
Langkah 2 dan 3: Optimumkan masalah untuk pelaksanaan perkakasan kuantum dan laksanakan menggunakan fungsi HiVQE Chemistry​
Sediakan gelung for untuk menjalankan pengiraan HiVQE dengan geometri menggunakan pilihan yang ditentukan di bawah. Job dihantar dalam gelung for. Dalam tutorial ini, anda akan menghantar enam geometri dan mendapatkan semula keputusan apabila semuanya selesai. Dalam jalankan fungsi utama, anda perlu menentukan max_states dan max_expansion_states untuk mengawal saiz maksimum matriks subruang dan mengawal berapa banyak keadaan yang boleh dijana menggunakan kaedah CI pengembangan klasik setiap iterasi. ID job fungsi akan disimpan dalam kamus dengan setiap label geometri untuk menjejak dan memproses output selanjutnya.
info_jobid = {}
for dis, geom in str_geometries.items():
hivqe_run = hivqe.run(
geometry=geom,
backend_name="",
max_states=40000,
max_expansion_states=100,
molecule_options=molecule_options,
hivqe_options=hivqe_options,
)
status = hivqe_run.status()
info_jobid[dis] = hivqe_run.job_id
print(info_jobid)
{'1.51': 'de3b8818-c9db-4fa3-a3c2-d51551c2dfaf', '1.91': '55d9467a-fc85-49a8-9bc6-8f6990e421e5', '2.40': '415112b3-69ff-4d53-8b10-cb4e3be68c9e', '3.10': 'ef67b600-3887-4225-b872-e354dfdf8454', '3.80': 'b16d3502-a9e4-4560-9775-852e9d07e70f', '4.50': '0c0bffc7-af77-4a56-a656-2a2610c991d6'}
Mari semak sama ada semua job masih berjalan atau sudah selesai.
completed_jobs_num = 0
running_jobs_num = 0
completed_jobs = {}
for i, info in enumerate(info_jobid.items()):
dis, job_id = info
submitted_job = catalog.get_job_by_id(job_id)
stat = submitted_job.status()
print(dis, submitted_job.job_id, stat)
if stat == "DONE":
completed_jobs_num += 1
completed_jobs[dis] = submitted_job
if (stat == "RUNNING") or (stat == "QUEUED"):
running_jobs_num += 1
print(
f"Completed {completed_jobs_num} job, Running or Queued {running_jobs_num} job"
)
1.51 de3b8818-c9db-4fa3-a3c2-d51551c2dfaf DONE
1.91 55d9467a-fc85-49a8-9bc6-8f6990e421e5 DONE
2.40 415112b3-69ff-4d53-8b10-cb4e3be68c9e DONE
3.10 ef67b600-3887-4225-b872-e354dfdf8454 DONE
3.80 b16d3502-a9e4-4560-9775-852e9d07e70f DONE
4.50 0c0bffc7-af77-4a56-a656-2a2610c991d6 DONE
Completed 6 job, Running or Queued 0 job
Setelah semua job selesai, mari kita dapatkan semula semua keputusan pengiraan.
hivqe_result = {}
if len(info_jobid) == completed_jobs_num:
print("All jobs are completed")
for i, job in enumerate(completed_jobs.items()):
dis, cal = job
print(dis, cal.result()["energy"])
hivqe_result[str(dis)] = cal.result()["energy"]
All jobs are completed
1.51 -407.8944801731773
1.91 -407.9800570932916
2.40 -407.9372992999806
3.10 -407.86278336000134
3.80 -407.83092972296157
4.50 -407.82971011225766
pprint.pprint(hivqe_result)
{'1.51': -407.8944801731773,
'1.91': -407.9800570932916,
'2.40': -407.9372992999806,
'3.10': -407.86278336000134,
'3.80': -407.83092972296157,
'4.50': -407.82971011225766}
Jumlah masa jalan QPU yang digunakan dalam job boleh dijejaki dengan log masuk ke IBM Quantum Platform dan melihat job yang dihantar dengan tag qunova-chemistry-hivqe.
Langkah 4: Pasca-proses dan bandingkan dengan kaedah klasik​
Pengiraan rujukan klasik (CASCI) boleh dijalankan untuk (10o,10e) bagi mengesahkan keputusan HiVQE.
str_geometries = {
"1.31": "S -1.250686 0.660708 -0.095168; Li -1.482812 0.453464 -1.369406; Li -0.911870 0.962810 1.762020",
"1.41": "S -1.244856 0.665971 -0.062773; Li -1.494574 0.442933 -1.434177; Li -0.905937 0.968078 1.794395",
"1.51": "S -1.239044 0.671232 -0.030374; Li -1.506327 0.432403 -1.498949; Li -0.899996 0.973348 1.826768",
"1.61": "S -1.233245 0.676492 0.002027; Li -1.518073 0.421873 -1.563722; Li -0.894049 0.978617 1.859141",
"1.71": "S -1.227453 0.681752 0.034429; Li -1.529816 0.411343 -1.628496; Li -0.888099 0.983887 1.891513",
"1.81": "S -1.221659 0.687012 0.066831; Li -1.541558 0.400813 -1.693270; Li -0.882150 0.989157 1.923885",
"1.91": "S -1.215858 0.692272 0.099232; Li -1.553305 0.390283 -1.758043; Li -0.876205 0.994426 1.956257",
"2.01": "S -1.209887 0.697544 0.131599; Li -1.565136 0.379748 -1.822800; Li -0.870344 0.999691 1.988646",
"2.11": "S -1.203945 0.702813 0.163973; Li -1.576953 0.369214 -1.887560; Li -0.864469 1.004956 2.021033",
"2.21": "S -1.198023 0.708081 0.196350; Li -1.588760 0.358680 -1.952322; Li -0.858584 1.010221 2.053417",
"2.30": "S -1.365426 0.717714 0.367060; Li -0.689401 0.458925 -1.828368; Li -1.500219 0.981173 2.255876",
"2.31": "S -1.192118 0.713348 0.228731; Li -1.600559 0.348146 -2.017085; Li -0.852690 1.015488 2.085800",
"2.40": "S -1.741432 0.680397 0.346702; Li -0.529307 0.488006 -1.729343; Li -1.284307 0.989409 2.177209",
"2.50": "S -1.885961 0.669986 0.365815; Li -0.461563 0.499084 -1.695846; Li -1.207523 0.988741 2.124599",
"2.60": "S -1.977163 0.665155 0.389784; Li -0.416654 0.504966 -1.683655; Li -1.161229 0.987690 2.088439",
"2.70": "S -2.063642 0.661518 0.418977; Li -0.367600 0.510505 -1.676408; Li -1.123804 0.985788 2.051998",
"2.80": "S -2.141072 0.659218 0.451663; Li -0.323153 0.515056 -1.673046; Li -1.090821 0.983538 2.015951",
"2.90": "S -2.212097 0.657968 0.487535; Li -0.281989 0.518909 -1.672407; Li -1.060960 0.980935 1.979440",
"3.00": "S -2.281477 0.657123 0.525155; Li -0.239607 0.523326 -1.668669; Li -1.033963 0.977363 1.938081",
"3.10": "S -2.347450 0.657089 0.566194; Li -0.199353 0.527517 -1.665148; Li -1.008243 0.973206 1.893522",
"3.20": "S -2.410882 0.657532 0.608912; Li -0.157788 0.532069 -1.659971; Li -0.986376 0.968211 1.845627",
"3.30": "S -2.470306 0.658818 0.654893; Li -0.118007 0.536237 -1.656311; Li -0.966733 0.962757 1.795986",
"3.40": "S -2.525776 0.660762 0.702910; Li -0.078312 0.540189 -1.654076; Li -0.950958 0.956861 1.745734",
"3.50": "S -2.576885 0.663376 0.752788; Li -0.039076 0.543706 -1.654536; Li -0.939085 0.950730 1.696316",
"3.60": "S -2.623930 0.666534 0.803853; Li 0.000274 0.546839 -1.657697; Li -0.931390 0.944439 1.648412",
"3.70": "S -2.667364 0.670217 0.856250; Li 0.039572 0.549616 -1.663265; Li -0.927254 0.937980 1.601583",
"3.80": "S -2.707255 0.674298 0.909161; Li 0.079218 0.552012 -1.671656; Li -0.927010 0.931502 1.557063",
"3.90": "S -2.744005 0.678718 0.962425; Li 0.119268 0.554073 -1.682595; Li -0.930310 0.925021 1.514738",
"4.00": "S -2.777891 0.683415 1.015798; Li 0.159751 0.555810 -1.696024; Li -0.936907 0.918587 1.474794",
"4.10": "S -2.809179 0.688333 1.069057; Li 0.200678 0.557234 -1.711873; Li -0.946546 0.912245 1.437385",
"4.20": "S -2.838194 0.693443 1.122205; Li 0.242066 0.558401 -1.729770; Li -0.958918 0.905968 1.402134",
"4.30": "S -2.864984 0.698619 1.174415; Li 0.283858 0.559186 -1.750539; Li -0.973920 0.900007 1.370693",
"4.40": "S -2.889984 0.703887 1.226140; Li 0.326068 0.559728 -1.773231; Li -0.991131 0.894196 1.341660",
"4.50": "S -2.913363 0.709175 1.276987; Li 0.368656 0.559989 -1.798088; Li -1.010340 0.888647 1.315670",
}
rhf_result = {}
casci_result = {}
cas_list = molecule_options["active_orbitals"]
distance_ref = []
for dis, geom in str_geometries.items():
distance_ref.append(dis)
mole = gto.M(atom=geom, basis=molecule_options["basis"])
mole.verbose = 0
# RHF energy
mf = scf.RHF(mole).run()
mo_occ = mf.mo_occ
num_elecs_as = int(sum([mo_occ[idx] for idx in cas_list]))
rhf_result[str(dis)] = mf.e_tot
# CASCI energy
casci_solver = mcscf.CASCI(mf, len(cas_list), num_elecs_as)
orbs = mcscf.addons.sort_mo(casci_solver, mf.mo_coeff, cas_list, base=0)
casci_solver.kernel(orbs)
casci_result[str(dis)] = casci_solver.e_tot
print(
f"d={dis:4.3} RHF Energy: {mf.e_tot:14.10}, CASCI Energy: {casci_solver.e_tot:14.10}"
)
d=1.3 RHF Energy: -407.7137006, CASCI Energy: -407.7193917
d=1.4 RHF Energy: -407.8183196, CASCI Energy: -407.8245211
d=1.5 RHF Energy: -407.8878013, CASCI Energy: -407.8944802
d=1.6 RHF Energy: -407.9315356, CASCI Energy: -407.9385663
d=1.7 RHF Energy: -407.9569034, CASCI Energy: -407.9641258
d=1.8 RHF Energy: -407.9693681, CASCI Energy: -407.9766313
d=1.9 RHF Energy: -407.9728592, CASCI Energy: -407.9800572
d=2.0 RHF Energy: -407.9701684, CASCI Energy: -407.9772549
d=2.1 RHF Energy: -407.9632701, CASCI Energy: -407.9702381
d=2.2 RHF Energy: -407.9535584, CASCI Energy: -407.9604007
d=2.3 RHF Energy: -407.9420173, CASCI Energy: -407.9487043
d=2.3 RHF Energy: -407.9420156, CASCI Energy: -407.9487024
d=2.4 RHF Energy: -407.9297216, CASCI Energy: -407.9372993
d=2.5 RHF Energy: -407.9172, CASCI Energy: -407.9261859
d=2.6 RHF Energy: -407.9061139, CASCI Energy: -407.915961
d=2.7 RHF Energy: -407.8937118, CASCI Energy: -407.904259
d=2.8 RHF Energy: -407.8816389, CASCI Energy: -407.8928292
d=2.9 RHF Energy: -407.8700448, CASCI Energy: -407.8819574
d=3.0 RHF Energy: -407.859054, CASCI Energy: -407.8719092
d=3.1 RHF Energy: -407.8487619, CASCI Energy: -407.8628304
d=3.2 RHF Energy: -407.8392304, CASCI Energy: -407.8548482
d=3.3 RHF Energy: -407.8304842, CASCI Energy: -407.8480217
d=3.4 RHF Energy: -407.8225124, CASCI Energy: -407.8423743
d=3.5 RHF Energy: -407.8152758, CASCI Energy: -407.8378892
d=3.6 RHF Energy: -407.8087161, CASCI Energy: -407.8345331
d=3.7 RHF Energy: -407.802764, CASCI Energy: -407.8322563
d=3.8 RHF Energy: -407.7973458, CASCI Energy: -407.83093
d=3.9 RHF Energy: -407.7923883, CASCI Energy: -407.8303555
d=4.0 RHF Energy: -407.7878216, CASCI Energy: -407.83025
d=4.1 RHF Energy: -407.783582, CASCI Energy: -407.8303243
d=4.2 RHF Energy: -407.7796124, CASCI Energy: -407.8303791
d=4.3 RHF Energy: -407.7758633, CASCI Energy: -407.8302885
d=4.4 RHF Energy: -407.7722923, CASCI Energy: -407.8300614
d=4.5 RHF Energy: -407.7688641, CASCI Energy: -407.829711
Memplot lengkung penceraian untuk Li_2S​
Mari plot dan bandingkan keputusan HiVQE dengan HF dan CASCI. Anda boleh perhatikan bahawa semua pengiraan HiVQE sepadan dengan baik dengan keputusan rujukan klasik (CASCI).
fig, ax = plt.subplots(1, 1)
hf_energy = [v for key, v in rhf_result.items()]
casci_energy = [v for key, v in casci_result.items()]
hivqe_energy = [v for key, v in hivqe_result.items()]
distance_ref = [float(key) for key, v in rhf_result.items()]
distance = [float(key) for key, v in hivqe_result.items()]
ax.plot(distance_ref, hf_energy, "-o", label="RHF", c="blue")
ax.plot(distance_ref, casci_energy, "-o", label="CASCI", c="green")
ax.plot(distance, hivqe_energy, "x", label="HiVQE", c="red", markersize=20)
ax.legend(fontsize=20)
ax.tick_params("both", labelsize=16)
ax.set_xlabel("Bond distance (angstrom)", size=20)
ax.set_ylabel("Energy (Ha)", size=20)
ax.set_title("Li2S PES curve", size=20)
fig.set_size_inches(14, 8)
Bahagian 2: FeP-NO (44Q)​
Langkah 1: Petakan input klasik kepada masalah kuantum​
Tentukan pilihan untuk pengiraan HiVQE
molecule_options = {
"basis": "631g*",
"active_orbitals": list(range(90, 112, 1)),
"frozen_orbitals": list(range(0, 90, 1)),
"charge": -1,
}
hivqe_options = {
"shots": 2000,
"max_iter": 40,
"ansatz": "epa",
"ansatz_entanglement": "linear",
"ansatz_reps": 2,
"amplitude_screening_tolerance": 1e-6,
}
Tentukan geometri FeP-NO dalam format kamus untuk jarak ikatan Fe-N yang berbeza bagi mengira lengkung PES.
geometry_1_75 = """
Fe 9.910596 31.534095 1.798088
N 10.557481 31.888419 -0.055204
N 11.823496 31.255002 2.384659
N 9.292831 30.783362 3.568730
N 8.036805 31.418327 1.124265
C 9.784765 32.177349 -1.158798
C 10.612656 32.501029 -2.296868
C 11.903375 32.404043 -1.876832
C 11.859093 32.028943 -0.483750
C 12.965737 31.464698 1.641427
C 14.146517 31.236323 2.440231
C 13.713061 30.885870 3.681911
C 12.268752 30.896411 3.634891
C 10.067717 30.486167 4.664747
C 9.246224 30.053411 5.772052
C 7.957075 30.082846 5.336488
C 7.995710 30.538421 3.967046
C 6.900258 31.104497 1.836595
C 5.722470 31.251707 1.015333
C 6.148430 31.668586 -0.207993
C 7.587039 31.767438 -0.130483
C 8.399453 32.134197 -1.192329
H 7.912872 32.388031 -2.131079
C 12.984883 31.836053 0.306093
H 13.955948 31.977044 -0.162626
C 11.453768 30.560663 4.708020
H 11.940677 30.298823 5.644352
C 6.877071 30.697580 3.164102
H 5.907240 30.476797 3.603674
H 12.813946 32.569160 -2.441577
H 10.236332 32.758110 -3.280309
H 15.164312 31.335191 2.080201
H 14.299625 30.629109 4.556760
H 9.626524 29.758225 6.743433
H 7.053076 29.823583 5.875809
H 4.709768 31.058315 1.350561
H 5.561898 31.886355 -1.093106
N 9.832739 33.209042 2.298783
O 9.346337 34.075996 1.606023
"""
geometry_2_00 = """
Fe 9.917990 31.445558 1.778346
N 10.556809 31.866188 -0.055498
N 11.814089 31.227003 2.372666
N 9.297875 30.758246 3.550104
N 8.043584 31.397768 1.120485
C 9.784831 32.164652 -1.160219
C 10.611624 32.501801 -2.293514
C 11.902858 32.406547 -1.875160
C 11.859552 32.017818 -0.486307
C 12.960503 31.454432 1.636717
C 14.140770 31.242960 2.439615
C 13.708543 30.884151 3.678983
C 12.266351 30.874173 3.627468
C 10.070264 30.465070 4.655102
C 9.247247 30.053101 5.766681
C 7.958085 30.091201 5.332866
C 7.998432 30.529979 3.958727
C 6.901428 31.093932 1.833807
C 5.723289 31.255057 1.016540
C 6.151314 31.670649 -0.206350
C 7.589736 31.755538 -0.133074
C 8.400230 32.124963 -1.194447
H 7.913264 32.386655 -2.130914
C 12.983905 31.827747 0.302415
H 13.955696 31.979687 -0.161365
C 11.454251 30.533644 4.698234
H 11.941002 30.276716 5.636156
C 6.877444 30.689985 3.159940
H 5.907605 30.480118 3.604825
H 12.813105 32.581608 -2.437367
H 10.233725 32.768337 -3.273979
H 15.157796 31.357524 2.082132
H 14.295001 30.638320 4.557047
H 9.626721 29.768762 6.741623
H 7.051752 29.847502 5.875478
H 4.709710 31.071712 1.354640
H 5.565103 31.898376 -1.089333
N 9.840508 33.353531 2.373019
O 9.344561 34.158205 1.637232
"""
geometry_5_00 = """
Fe 9.918629 31.289202 1.717339
N 10.542914 31.832173 -0.080685
N 11.795572 31.199413 2.341831
N 9.294593 30.741247 3.513929
N 8.042689 31.359481 1.087282
C 9.775254 32.111817 -1.200449
C 10.600219 32.479101 -2.319680
C 11.891090 32.425876 -1.887580
C 11.847694 32.024341 -0.507342
C 12.945734 31.464689 1.611366
C 14.116395 31.289997 2.423572
C 13.685777 30.915122 3.663719
C 12.252381 30.861042 3.608186
C 10.062170 30.463021 4.634102
C 9.236749 30.104333 5.755782
C 7.945687 30.161198 5.324720
C 7.989641 30.552269 3.941498
C 6.892881 31.087489 1.815829
C 5.722676 31.253502 1.001149
C 6.153153 31.631057 -0.238233
C 7.586010 31.695401 -0.179773
C 8.390724 32.047572 -1.247553
H 7.903308 32.291586 -2.187969
C 12.973334 31.849872 0.283741
H 13.944682 32.031190 -0.169145
C 11.447158 30.518591 4.678739
H 11.934423 30.277429 5.619969
C 6.864795 30.711643 3.146118
H 5.893357 30.532078 3.599511
H 12.800139 32.636412 -2.439296
H 10.224017 32.743662 -3.301293
H 15.131785 31.441247 2.076257
H 14.273933 30.694315 4.546802
H 9.612512 29.848040 6.739754
H 7.036117 29.960530 5.879248
H 4.707408 31.099933 1.347803
H 5.564992 31.851940 -1.121294
N 9.666041 36.091609 3.085945
O 9.598728 37.226756 3.411299
"""
str_geometries = {
"1.75": geometry_1_75,
"2.00": geometry_2_00,
"5.00": geometry_5_00,
}
hivqe_result = {}
{'5.0': '\nFe 9.918629 31.289202 1.717339\nN 10.542914 31.832173 -0.080685\nN 11.795572 31.199413 2.341831\nN 9.294593 30.741247 3.513929\nN 8.042689 31.359481 1.087282\nC 9.775254 32.111817 -1.200449\nC 10.600219 32.479101 -2.319680\nC 11.891090 32.425876 -1.887580\nC 11.847694 32.024341 -0.507342\nC 12.945734 31.464689 1.611366\nC 14.116395 31.289997 2.423572\nC 13.685777 30.915122 3.663719\nC 12.252381 30.861042 3.608186\nC 10.062170 30.463021 4.634102\nC 9.236749 30.104333 5.755782\nC 7.945687 30.161198 5.324720\nC 7.989641 30.552269 3.941498\nC 6.892881 31.087489 1.815829\nC 5.722676 31.253502 1.001149\nC 6.153153 31.631057 -0.238233\nC 7.586010 31.695401 -0.179773\nC 8.390724 32.047572 -1.247553\nH 7.903308 32.291586 -2.187969\nC 12.973334 31.849872 0.283741\nH 13.944682 32.031190 -0.169145\nC 11.447158 30.518591 4.678739\nH 11.934423 30.277429 5.619969\nC 6.864795 30.711643 3.146118\nH 5.893357 30.532078 3.599511\nH 12.800139 32.636412 -2.439296\nH 10.224017 32.743662 -3.301293\nH 15.131785 31.441247 2.076257\nH 14.273933 30.694315 4.546802\nH 9.612512 29.848040 6.739754\nH 7.036117 29.960530 5.879248\nH 4.707408 31.099933 1.347803\nH 5.564992 31.851940 -1.121294\nN 9.666041 36.091609 3.085945\nO 9.598728 37.226756 3.411299\n'}
geometry_1_75 = """
Fe 9.910596 31.534095 1.798088
N 10.557481 31.888419 -0.055204
N 11.823496 31.255002 2.384659
N 9.292831 30.783362 3.568730
N 8.036805 31.418327 1.124265
C 9.784765 32.177349 -1.158798
C 10.612656 32.501029 -2.296868
C 11.903375 32.404043 -1.876832
C 11.859093 32.028943 -0.483750
C 12.965737 31.464698 1.641427
C 14.146517 31.236323 2.440231
C 13.713061 30.885870 3.681911
C 12.268752 30.896411 3.634891
C 10.067717 30.486167 4.664747
C 9.246224 30.053411 5.772052
C 7.957075 30.082846 5.336488
C 7.995710 30.538421 3.967046
C 6.900258 31.104497 1.836595
C 5.722470 31.251707 1.015333
C 6.148430 31.668586 -0.207993
C 7.587039 31.767438 -0.130483
C 8.399453 32.134197 -1.192329
H 7.912872 32.388031 -2.131079
C 12.984883 31.836053 0.306093
H 13.955948 31.977044 -0.162626
C 11.453768 30.560663 4.708020
H 11.940677 30.298823 5.644352
C 6.877071 30.697580 3.164102
H 5.907240 30.476797 3.603674
H 12.813946 32.569160 -2.441577
H 10.236332 32.758110 -3.280309
H 15.164312 31.335191 2.080201
H 14.299625 30.629109 4.556760
H 9.626524 29.758225 6.743433
H 7.053076 29.823583 5.875809
H 4.709768 31.058315 1.350561
H 5.561898 31.886355 -1.093106
N 9.832739 33.209042 2.298783
O 9.346337 34.075996 1.606023
"""
geometry_2_00 = """
Fe 9.917990 31.445558 1.778346
N 10.556809 31.866188 -0.055498
N 11.814089 31.227003 2.372666
N 9.297875 30.758246 3.550104
N 8.043584 31.397768 1.120485
C 9.784831 32.164652 -1.160219
C 10.611624 32.501801 -2.293514
C 11.902858 32.406547 -1.875160
C 11.859552 32.017818 -0.486307
C 12.960503 31.454432 1.636717
C 14.140770 31.242960 2.439615
C 13.708543 30.884151 3.678983
C 12.266351 30.874173 3.627468
C 10.070264 30.465070 4.655102
C 9.247247 30.053101 5.766681
C 7.958085 30.091201 5.332866
C 7.998432 30.529979 3.958727
C 6.901428 31.093932 1.833807
C 5.723289 31.255057 1.016540
C 6.151314 31.670649 -0.206350
C 7.589736 31.755538 -0.133074
C 8.400230 32.124963 -1.194447
H 7.913264 32.386655 -2.130914
C 12.983905 31.827747 0.302415
H 13.955696 31.979687 -0.161365
C 11.454251 30.533644 4.698234
H 11.941002 30.276716 5.636156
C 6.877444 30.689985 3.159940
H 5.907605 30.480118 3.604825
H 12.813105 32.581608 -2.437367
H 10.233725 32.768337 -3.273979
H 15.157796 31.357524 2.082132
H 14.295001 30.638320 4.557047
H 9.626721 29.768762 6.741623
H 7.051752 29.847502 5.875478
H 4.709710 31.071712 1.354640
H 5.565103 31.898376 -1.089333
N 9.840508 33.353531 2.373019
O 9.344561 34.158205 1.637232
"""
geometry_5_00 = """
Fe 9.918629 31.289202 1.717339
N 10.542914 31.832173 -0.080685
N 11.795572 31.199413 2.341831
N 9.294593 30.741247 3.513929
N 8.042689 31.359481 1.087282
C 9.775254 32.111817 -1.200449
C 10.600219 32.479101 -2.319680
C 11.891090 32.425876 -1.887580
C 11.847694 32.024341 -0.507342
C 12.945734 31.464689 1.611366
C 14.116395 31.289997 2.423572
C 13.685777 30.915122 3.663719
C 12.252381 30.861042 3.608186
C 10.062170 30.463021 4.634102
C 9.236749 30.104333 5.755782
C 7.945687 30.161198 5.324720
C 7.989641 30.552269 3.941498
C 6.892881 31.087489 1.815829
C 5.722676 31.253502 1.001149
C 6.153153 31.631057 -0.238233
C 7.586010 31.695401 -0.179773
C 8.390724 32.047572 -1.247553
H 7.903308 32.291586 -2.187969
C 12.973334 31.849872 0.283741
H 13.944682 32.031190 -0.169145
C 11.447158 30.518591 4.678739
H 11.934423 30.277429 5.619969
C 6.864795 30.711643 3.146118
H 5.893357 30.532078 3.599511
H 12.800139 32.636412 -2.439296
H 10.224017 32.743662 -3.301293
H 15.131785 31.441247 2.076257
H 14.273933 30.694315 4.546802
H 9.612512 29.848040 6.739754
H 7.036117 29.960530 5.879248
H 4.707408 31.099933 1.347803
H 5.564992 31.851940 -1.121294
N 9.666041 36.091609 3.085945
O 9.598728 37.226756 3.411299
"""
str_geometries = {
"1.75": geometry_1_75,
"2.00": geometry_2_00,
"5.00": geometry_5_00,
}
hivqe_result = {}
{'5.0': '\nFe 9.918629 31.289202 1.717339\nN 10.542914 31.832173 -0.080685\nN 11.795572 31.199413 2.341831\nN 9.294593 30.741247 3.513929\nN 8.042689 31.359481 1.087282\nC 9.775254 32.111817 -1.200449\nC 10.600219 32.479101 -2.319680\nC 11.891090 32.425876 -1.887580\nC 11.847694 32.024341 -0.507342\nC 12.945734 31.464689 1.611366\nC 14.116395 31.289997 2.423572\nC 13.685777 30.915122 3.663719\nC 12.252381 30.861042 3.608186\nC 10.062170 30.463021 4.634102\nC 9.236749 30.104333 5.755782\nC 7.945687 30.161198 5.324720\nC 7.989641 30.552269 3.941498\nC 6.892881 31.087489 1.815829\nC 5.722676 31.253502 1.001149\nC 6.153153 31.631057 -0.238233\nC 7.586010 31.695401 -0.179773\nC 8.390724 32.047572 -1.247553\nH 7.903308 32.291586 -2.187969\nC 12.973334 31.849872 0.283741\nH 13.944682 32.031190 -0.169145\nC 11.447158 30.518591 4.678739\nH 11.934423 30.277429 5.619969\nC 6.864795 30.711643 3.146118\nH 5.893357 30.532078 3.599511\nH 12.800139 32.636412 -2.439296\nH 10.224017 32.743662 -3.301293\nH 15.131785 31.441247 2.076257\nH 14.273933 30.694315 4.546802\nH 9.612512 29.848040 6.739754\nH 7.036117 29.960530 5.879248\nH 4.707408 31.099933 1.347803\nH 5.564992 31.851940 -1.121294\nN 9.666041 36.091609 3.085945\nO 9.598728 37.226756 3.411299\n'}
Langkah 2 dan 3: Optimumkan masalah untuk pelaksanaan perkakasan kuantum dan laksanakan menggunakan fungsi HiVQE Chemistry​
Berdasarkan persediaan HiVQE dan geometri, dapatkan keputusan secara berurutan.
Hantar pengiraan d(Fe-N) = 1.75 .​
hivqe_run_1_75 = hivqe.run(
geometry=str_geometries["1.75"],
backend_name="",
max_states=400000000,
max_expansion_states=100,
molecule_options=molecule_options,
hivqe_options=hivqe_options,
)
info_jobid_1_75 = hivqe_run_1_75.job_id
Jejak job dan dapatkan semula keputusan untuk pengiraan d(Fe-N) = 1.75 .
submitted_job_1_75 = catalog.get_job_by_id(info_jobid_1_75)
stat = submitted_job_1_75.status()
print(submitted_job_1_75.job_id, stat)
if stat == "DONE":
hivqe_run_1_75_energy = submitted_job_1_75.result()["energy"]
print(f"Completed HiVQE calculation, Energy {hivqe_run_1_75_energy}")
hivqe_result["1.75"] = hivqe_run_1_75_energy
Hantar pengiraan d(Fe-N) = 2.00 .​
hivqe_run_2_00 = hivqe.run(
geometry=str_geometries["2.00"],
backend_name="",
max_states=400000000,
max_expansion_states=100,
molecule_options=molecule_options,
hivqe_options=hivqe_options,
)
info_jobid_2_00 = hivqe_run_2_00.job_id
Jejak job dan dapatkan semula keputusan untuk pengiraan d(Fe-N) = 2.00 .
submitted_job_2_00 = catalog.get_job_by_id(info_jobid_2_00)
stat = submitted_job_2_00.status()
print(submitted_job_2_00.job_id, stat)
if stat == "DONE":
hivqe_run_2_00_energy = submitted_job_2_00.result()["energy"]
print(f"Completed HiVQE calculation, Energy {hivqe_run_2_00_energy}")
hivqe_result["2.00"] = hivqe_run_2_00_energy
Hantar pengiraan d(Fe-N) = 5.00 .​
hivqe_run_5_00 = hivqe.run(
geometry=str_geometries["5.00"],
backend_name="",
max_states=400000000,
max_expansion_states=100,
molecule_options=molecule_options,
hivqe_options=hivqe_options,
)
info_jobid_5_00 = hivqe_run_5_00.job_id
Jejak job dan dapatkan semula keputusan untuk pengiraan d(Fe-N) = 5.00 .
submitted_job_5_00 = catalog.get_job_by_id(info_jobid_5_00)
stat = submitted_job_5_00.status()
print(submitted_job_5_00.job_id, stat)
if stat == "DONE":
hivqe_run_5_00_energy = submitted_job_5_00.result()["energy"]
print(f"Completed HiVQE calculation, Energy {hivqe_run_5_00_energy}")
hivqe_result["5.00"] = hivqe_run_5_00_energy
hivqe_result = {
"1.75": -2373.681781,
"2.00": -2373.694128,
"5.00": -2373.637807,
}
Langkah 4: Pasca-proses dan bandingkan dengan kaedah klasik​
Keputusan pengiraan rujukan klasik (CASCI-DMRG, maxM=800) disediakan untuk (22o,22e) bagi mengesahkan keputusan HiVQE.
rhf_result = {
"1.75": -2373.59331683504,
"2.00": -2373.60640773065,
"5.00": -2373.50214278007,
}
casci_result = {"1.75": -2373.6827, "2.00": -2373.6948, "5.00": -2373.6393}
fig, ax = plt.subplots(1, 1)
hf_energy = [v for key, v in rhf_result.items()]
casci_energy = [v for key, v in casci_result.items()]
hivqe_energy = [v for key, v in hivqe_result.items()]
distance_ref = [float(key) for key, v in rhf_result.items()]
distance = [float(key) for key, v in hivqe_result.items()]
ax.plot(distance_ref, hf_energy, "-o", label="RHF", c="blue")
ax.plot(distance_ref, casci_energy, "-o", label="CASCI", c="green")
ax.plot(distance, hivqe_energy, "x", label="HiVQE", c="red", markersize=20)
ax.legend(fontsize=20)
ax.tick_params("both", labelsize=16)
ax.set_xlabel("Fe-N bond distance ($\AA$)", size=20)
ax.set_ylabel("Energy (Ha)", size=20)
ax.set_title("FeP-NO PES curve", size=20)
fig.set_size_inches(14, 8)
Tinjauan tutorial​
Sila ambil tinjauan ringkas ini untuk memberikan maklum balas tentang tutorial ini. Pandangan anda akan membantu kami meningkatkan kandungan dan pengalaman pengguna kami.
Note: This survey is provided by IBM Quantum and relates to the original English content. To give feedback on doQumentation's website, translations, or code execution, please open a GitHub issue.
Source: IBM Quantum docs — updated 24 Feb 2026
English version on doQumentation — updated 7 Mei 2026
This translation based on the English version of 9 Apr 2026